EAST LANSING, Mich. (Interstat) — UCLA (42-4, 16-2 Big Ten) seeks a three-game sweep of Michigan State (16-27, 6-12) on Sunday afternoon at McLane Stadium.

The Bruins have dominated the series, winning 4-3 on Saturday and 4-1 on Friday. UCLA carries a 42-4 overall record into the finale, while the Spartans have lost 27 of 43 games.

For UCLA, right-hander Michael Barnett is a key figure. In Saturday’s 4-3 win, Barnett allowed two earned runs on zero hits over 4.1 innings with one strikeout. Over his last four starts (Interstat) — all victories (Interstat) — he has posted a 2.89 ERA with 12 strikeouts across 18.2 innings.

Michigan State counters with right-hander Logan Pikur. In Saturday’s loss, Pikur threw four innings, surrendering zero earned runs on two hits with three strikeouts. Over his last eight appearances, he has a 1.46 ERA and 15 strikeouts in 18.1 innings.

The Bruins’ offense has been powered by catcher Cashel Dugger, who went 3-for-3 with two RBIs on Saturday. UCLA has won nine of its last 10 games, with the lone loss coming April 26 to Sacramento State.

Michigan State has lost five of its last six. Parker Picot drove in the Spartans’ only run Saturday with a single.

Interstat’s game simulator projects an 8-5 UCLA victory.

The game is the final contest of the three-game Big Ten series. UCLA travels to Loyola Marymount on Tuesday, while Michigan State hosts Bowling Green on Tuesday.